(1/2)^n-4=2^4n+10

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Solution for (1/2)^n-4=2^4n+10 equation: 



(1/2)^n-4=2^4n+10

We move all terms to the left:

(1/2)^n-4-(2^4n+10)=0



Domain of the equation: 2)^n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+1/2)^n-(2^4n+10)-4=0

We get rid of parentheses

(+1/2)^n-2^4n-10-4=0

We multiply all the terms by the denominator


(+1-2^4n*2)^n-10*2)^n-4*2)^n=0

Wy multiply elements

-40n^2+(+1-2^4n*2)^n=0

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